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----Explanation for aptitudes are listed below ----
10 june 11
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| 2. | Look at this series: 53, 53, 40, 40, 27, 27, ... What number should come next? | |||||||
Answer: Option B Explanation: In this series, each number is repeated, then 13 is subtracted to arrive at the next number. |
3.If one-third of one-fourth of a number is 15, then three-tenth of that number is: | ||||||||||||||||||||||
Answer: Option D Explanation: Let the number be x.
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2 june 11
| 1. | A man completes | ||||||||||||||||||||||||||||||||||||||||||||
Answer: Option B Explanation:
Let the required number of days be x.
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| 2. | In the series 2, 6, 18, 54, ...... what will be the 8th term ? | |||||||
Answer: Option B Explanation: Clearly, 2 x 3 = 6, 6 x 3 = 18, 18 x 3 = 54,..... So, the series is a G.P. in which a = 2, r = 3. Therefore 8th term = ar8-1 = ar7 = 2 x 37 = (2 x 2187) = 4374. |
3. Finf the next number?? 3, 10, 101,? | ||||||||
Answer: Option C Explanation: Each term in the series is obtained by adding 1 to the square of the preceding term. So, missing term = (101)2 + 1 = 10202. |
| 3. | If the two strings are identical, then strcmp() function returns | |||||||
Answer: Option C Explanation: Declaration: strcmp(const char *s1, const char*s2); The strcmp return an int value that is if s1 < s2 returns a value < 0 if s1 == s2 returns 0 if s1 > s2 returns a value > 0 |
1 july 11
| 1. | Arrange the words given below in a meaningful sequence.
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Answer: Option C Explanation: The correct order is :
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| 2. | harvest | |||||||
Answer: Option D Explanation: To harvest something, one must have a crop, which is the essential element for this item. Autumn (choice a) is not the only time crops are harvested. There may not be enough of a crop to stockpile (choice b), and you can harvest crops without a tractor (choice c). |
| 3. | What was the day of the week on 28th May, 2006? | |||||||
Answer: Option D Explanation: 28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006) Odd days in 1600 years = 0 Odd days in 400 years = 0 5 years = (4 ordinary years + 1 leap year) = (4 x 1 + 1 x 2) Total number of odd days = (0 + 0 + 6 + 1) = 7 Given day is Sunday. |
27 june 11
| 1) | If x and y are the two digits of the number 653 xy such that this number is divisible by 80, then x + y = ? | |||||||||
Answer: Option A Explanation: 80 = 2 x 5 x 8 Since 653 xy is divisible by 2 and 5 both, so y = 0. Now, 653 x0 is divisible by 8, so 3x0 should be divisible by 8. This happens when x = 2 or 6. |
| 2. | In a division sum, the remainder is 0. As student mistook the divisor by 12 instead of 21 and obtained 35 as quotient. What is the correct quotient ? | |||||||
Answer: Option D Explanation: Number = (12 x 35) Correct Quotient = 420 ÷ 21 = 20 |
26 june 11
| 1) | On dividing a number by 5, we get 3 as remainder. What will the remainder when the square of the this number is divided by 5 ? | |||||||
Answer: Option D Explanation: Let the number be x and on dividing x by 5, we get k as quotient and 3 as remainder. = (25k2 + 30k + 9) = 5(5k2 + 6k + 1) + 4 |
| 2) | n is a whole number which when divided by 4 gives 3 as remainder. What will be the remainder when 2n is divided by 4 ? | |||||||
Answer: Option B Explanation: Let n = 4q + 3. Then 2n = 8q + 6 = 4(2q + 1 ) + 2. Thus, when 2n is divided by 4, the remainder is 2. |
25 june 11
| 1. | If the number 481 * 673 is completely divisible by 9, then the smallest whole number in place of * will be: | |||||||||
Answer: Option D Explanation: Sum of digits = (4 + 8 + 1 + x + 6 + 7 + 3) = (29 + x), which must be divisible by 9. |
| 2. | If n is a natural number, then (6n2 + 6n) is always divisible by: | |||||||
Answer: Option B Explanation: (6n2 + 6n) = 6n(n + 1), which is always divisible by 6 and 12 both, since n(n + 1) is always even. |
24 june 11
| 1. | The difference of two numbers is 1365. On dividing the larger number by the smaller, we get 6 as quotient and the 15 as remainder. What is the smaller number ? | |||||||
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Explanation:
Let the smaller number be x. Then larger number = (x + 1365).
| 2. | What is the unit digit in {(6374)1793 x (625)317 x (341491)}? | |||||||
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Answer: Option A
Explanation:
Unit digit in (6374)1793 = Unit digint in (4)1793
= Unit digit in [(42)896 x 4]
= Unit digit in (6 x 4) = 4
Unit digit in (625)317 = Unit digit in (5)317 = 5
Unit digit in (341)491 = Unit digit in (1)491 = 1
Required digit = Unit digit in (4 x 5 x 1) = 0.